Answer
Domain: all real numbers except $x=2$
Work Step by Step
$\frac{x^2+x-2}{x^2-4x+4}$
The denominator must be different from $0$.
$x^2-4x+4\ne0$
$x^2-2(2)x+2^2\ne0$
$(x-2)^2\ne0$
$(x-2)\ne0$
$x\ne2$
You can help us out by revising, improving and updating this answer.
Update this answerAfter you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.