Chapter 4 - 4.3 - Conics - 4.3 Exercises - Page 337: 15

Focus: $(0,\frac{1}{2})$ Directrix: $y=-\frac{1}{2}$

Parabola in the standard form with the vertex at origin (vertical axis): $x^2=4py$ $y=\frac{1}{2}x^2$ $x^2=2y$ That is: $4py=2y$ $p=\frac{1}{2}$ $(0,p)=(0,\frac{1}{2})$ Directrix: $y=-p=-\frac{1}{2}$