Answer
The equation matches with the graph labeled as (d).
Work Step by Step
$x^2-\frac{y^2}{9}=1$
$\frac{(x-0)^2}{1^2}-\frac{(y-0)^2}{3^2}=1$
It is a hyperbola with center at origin $(0,0)$ and the transverse axis is horizontal.
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