Algebra and Trigonometry 10th Edition

Published by Cengage Learning
ISBN 10: 9781337271172
ISBN 13: 978-1-33727-117-2

Chapter 4 - 4.3 - Conics - 4.3 Exercises - Page 337: 13

Answer

The equation matches with the graph labeled as (a).

Work Step by Step

$y^2-9x^2=9$ $\frac{(y-0)^2}{3^2}-\frac{(x-0)^2}{1^2}=1$ It is a hyperbola with center at origin $(0,0)$ and the transverse axis is vertical.
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