Answer
$f(x)(x-1-4i)(x-1+4i)$
The zeros:
$x=1+4i$
$x=1-4i$
Work Step by Step
$x^2-2x+17=0~~$ ($a=1,b=-2,c=17$):
$x=\frac{-b±\sqrt {b^2-4ac}}{2a}=\frac{-(-2)±\sqrt {(-2)^2-4(1)(17)}}{2(1)}=\frac{2±\sqrt {-64}}{2}=\frac{2±8i}{2}=1±4i$
$x=1+4i$ or $x=1-4i$
$f(x)=[x-(1+4i)][x-(1-4i)]=(x-1-4i)(x-1+4i)$
