Answer
$f(x)=(x+6i)(x-6i)$
The zeros:
$x=-6i$
$x=6i$
Work Step by Step
$f(x)=x^2+36$
$f(x)=x^2-(6i)^2$
$f(x)=(x+6i)(x-6i)$
The zeros:
$0=(x+6i)(x-6i)$
$x+6i=0$
$x=-6i$
$x-6i=0$
$x=6i$
Algebra and Trigonometry 10th Edition
by Larson, Ron
Published by
Cengage Learning
ISBN 10:
9781337271172
ISBN 13:
978-1-33727-117-2
Chapter 3 - 3.4 - Zeroes of Polynomial Functions - 3.4 Exercises - Page 284: 61
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