Answer
2h+4x+3
Work Step by Step
$\frac{f(x+h)-f(x)}{h}=\frac{(2(x+h)^2+3(x+h)-1)-(2x^2+3x-1)}{h}$
$=\frac{(2h^2+4hx+3h+2x^2+3x-1)-(2x^2+3x-1)}{h}$
$=\frac{2h^2+4hx+3h}{h}=2h+4x+3$
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