Answer
(a) $h(2)=-1$
(b) $h(-1)=-1$
(c) $h(x+1)=-x^2-x+1$
Work Step by Step
$h(t)=-t^2+t+1$
(a) $h(2)=-2^2+2+1=-4+3=-1$
(b) $h(-1)=-(-1)^2+(-1)+1=-4+3=-1-1+1=-1$
(c) $h(x+1)=-(x+1)^2+(x+1)+1=-x^2-2x-1+x+1+1=-x^2-x+1$
Algebra and Trigonometry 10th Edition
by Larson, Ron
Published by
Cengage Learning
ISBN 10:
9781337271172
ISBN 13:
978-1-33727-117-2
Chapter 2 - 2.2 - Functions - 2.2 Exercises - Page 182: 22
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