Answer
(a) $g(2)=15$
(b) $g(t-2)=4t^2-19t+27$
(c) $g(t)-g(2)=4t^2-3t-10$
Work Step by Step
$g(t)=4t^2-3t+5$
(a) $g(2)=4(2)^2-3(2)+5=16-6+5=15$
(b) $g(t-2)=4(t-2)^2-3(t-2)+5=4(t^2-4t+4)-3(t-2)+5=4t^2-16t+16-3t+6+5=4t^2-19t+27$
(c) $g(t)-g(2)=4t^2-3t+5-15=4t^2-3t-10$