Algebra and Trigonometry 10th Edition

Published by Cengage Learning
ISBN 10: 9781337271172
ISBN 13: 978-1-33727-117-2

Chapter 2 - 2.2 - Functions - 2.2 Exercises - Page 182: 20

Answer

(a) $V(3)=36\pi$ (b) $V(\frac{3}{2})=\frac{9}{2}\pi$ (c) $V(2r)=\frac{32}{3}\pi r ^3 $

Work Step by Step

$V(r)=\frac{4}{3}\pi r^3$ (a) $V(3)=\frac{4}{3}\pi (3^3)=\frac{4}{3}\pi (27)=36\pi$ (b) $V(\frac{3}{2})=\frac{4}{3}\pi (\frac{3}{2})^3=\frac{4}{3}\pi (\frac{27}{8})=\frac{9}{2}\pi$ (c) $V(2r)=\frac{4}{3}\pi (2r)^3=\frac{4}{3}\pi (8r^3)=\frac{32}{3}\pi r^3$
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