Answer
840 distinguishable permutations.
Work Step by Step
2 A's, 1 G, 3 E's and 1 M. Total: 7 letters.
$\frac{7!}{2!~1!~3!~1!}=\frac{5040}{6}=840$
Algebra and Trigonometry 10th Edition
by Larson, Ron
Published by
Cengage Learning
ISBN 10:
9781337271172
ISBN 13:
978-1-33727-117-2
Chapter 11824 - 11.6 - Counting Principles - 11.6 Exercises - Page 824: 43
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