Answer
$_{12}P_2=132$
Work Step by Step
$_nP_r=\frac{n!}{(n-r)!}$
$_{12}P_2=\frac{12!}{(12-2)!}=\frac{12\times11\times10!}{10!}=132$
Algebra and Trigonometry 10th Edition
by Larson, Ron
Published by
Cengage Learning
ISBN 10:
9781337271172
ISBN 13:
978-1-33727-117-2
Chapter 11824 - 11.6 - Counting Principles - 11.6 Exercises - Page 824: 33
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