Answer
$P_{k+1}=\frac{3}{(k+3)(k+4)}$
Work Step by Step
$P_k=\frac{3}{(k+2)(k+3)}$
$P_{k+1}=\frac{3}{[(k+1)+2][(k+1)+3]}=\frac{3}{(k+3)(k+4)}$
Algebra and Trigonometry 10th Edition
by Larson, Ron
Published by
Cengage Learning
ISBN 10:
9781337271172
ISBN 13:
978-1-33727-117-2
Chapter 11 - 11.4 - Mathematical Induction - 11.4 Exercises - Page 806: 9
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