Answer
$P_{k+1}=\frac{(k+1)^2}{2(k+2)^2}$
Work Step by Step
$P_k=\frac{k^2}{2(k+1)^2}$
$P_{k+1}=\frac{(k+1)^2}{2[(k+1)+1]^2}=\frac{(k+1)^2}{2(k+2)^2}$
Algebra and Trigonometry 10th Edition
by Larson, Ron
Published by
Cengage Learning
ISBN 10:
9781337271172
ISBN 13:
978-1-33727-117-2
Chapter 11 - 11.4 - Mathematical Induction - 11.4 Exercises - Page 806: 10
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