Answer
$P_{k+1}=(k+1)^2(k+4)^2$
Work Step by Step
$P_k=k^2(k+3)^2$
$P_{k+1}=(k+1)^2[(k+1)+3]^2=(k+1)^2(k+4)^2$
Algebra and Trigonometry 10th Edition
by Larson, Ron
Published by
Cengage Learning
ISBN 10:
9781337271172
ISBN 13:
978-1-33727-117-2
Chapter 11 - 11.4 - Mathematical Induction - 11.4 Exercises - Page 806: 7
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