Algebra and Trigonometry 10th Edition

Published by Cengage Learning
ISBN 10: 9781337271172
ISBN 13: 978-1-33727-117-2

Chapter 10 - Review Exercises - Page 763: 108

Answer

$x=3; y=-2$

Work Step by Step

The general form of a matrix of order $ 2 \times 2$ is: $det \ A=\begin{vmatrix} p & q \\ r & s\end{vmatrix}=ps-qr$ Now, $|A|=\begin{vmatrix} 3 & 8 \\ 9 & -5 \end{vmatrix}=-87$ Since the determinant is not zero, we will use Cramers Rule. $x=\dfrac{\begin{vmatrix} -7 & 8 \\37 & -5 \end{vmatrix}}{-87}=\dfrac{-261}{-87}=3$ and $y=\dfrac{\begin{vmatrix} 3 & -7 \\9& 37 \end{vmatrix}}{-87}=\dfrac{174}{-87}=-2$ So, $x=3; y=-2$
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