Answer
$-6$
Work Step by Step
The general form of a matrix of order $ 2 \times 2$ is:
$det \ A=\begin{bmatrix} p & q \\ r & s\end{bmatrix}=ps-qr$
Since Row-1 has the most zeroes, we choose $R_1$. It has sign array $(+,+)$ as we go to the right.
Now, $det \ A =-2 \begin{bmatrix} -1 & 0 \\ 1 & -3 \end{bmatrix}-0+0=-2(3-0)=-6$
