Algebra and Trigonometry 10th Edition

Published by Cengage Learning
ISBN 10: 9781337271172
ISBN 13: 978-1-33727-117-2

Chapter 10 - Review Exercises - Page 763: 106

Answer

$-23$

Work Step by Step

The general form of a matrix of order $ 2 \times 2$ is: $det \ A=\begin{vmatrix} p & q \\ r & s\end{vmatrix}=ps-qr$ Since Column-1 has the most zeroes, we choose Column-1. Now, $det \ A =1\begin{vmatrix} 1 & 2 \\ 1 & -2 \end{vmatrix}-(-4) 1\begin{vmatrix} 1 & 4 \\ 1 & -1 \end{vmatrix}+0 =-23$
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