Answer
$x=-2; y=1$
Work Step by Step
The system can be written as: $AX=B$
where, $B= \begin{bmatrix} x \\ y \end{bmatrix}$
Thus, $X=A^{-1} B = \begin{bmatrix} -9/2 & -1 \\ -19/2 & -2 \end{bmatrix}
\begin{bmatrix} -10 \\ 47 \end{bmatrix} =\begin{bmatrix} -2 \\ 1 \end{bmatrix}$
So, $X= \begin{bmatrix} x \\ y \end{bmatrix}=\begin{bmatrix} -2 \\ 1 \end{bmatrix}$
Therefore, $x=-2; y=1$
