Answer
$x=-6; y=-1$
Work Step by Step
The system can be written as: $AX=B$
where, $B= \begin{bmatrix} x \\ y \end{bmatrix}$
Thus, $X=A^{-1} B = \begin{bmatrix} -17 & -10 \\ -5 & -3 \end{bmatrix}
\begin{bmatrix} 8 \\ -13 \end{bmatrix} = \begin{bmatrix} (-17) (8)+(-10)(-13) \\ (-5) (8) +(-3)(-13) \end{bmatrix}$
So, $X= \begin{bmatrix} x \\ y \end{bmatrix}=\begin{bmatrix} -6 \\ -1 \end{bmatrix}$
Therefore, $x=-6; y=-1$
