Answer
$x^2+\frac{7}{30}x-\frac{1}{15}=0$
Work Step by Step
Write the quadratic as the product of two linear factors and the leading coefficient: $a(x-r_1)(x-r_2)=0$, where $r_1$ and $r_2$ are the solutions.
$a(x-\frac{1}{6})[x-(-\frac{2}{5})]=0~~$ (Make $a=1$ since it can be any real number except $0$)
$(x-\frac{1}{6})(x+\frac{2}{5})=0$
$x^2+\frac{2}{5}x-\frac{1}{6}x-\frac{2}{30}=0$
$x^2+\frac{7}{30}x-\frac{1}{15}=0$ (general form)
