Algebra and Trigonometry 10th Edition

Published by Cengage Learning
ISBN 10: 9781337271172
ISBN 13: 978-1-33727-117-2

Chapter 1 - 1.4 - Quadratic Equations and Applications - 1.4 Exercises - Page 113: 119b

Answer

$30\sqrt 6$ feet

Work Step by Step

In part $a)$ we found the equation connecting $l$ and $x$: $l^2-x^2=225$ Substitute $l=75$ and solve the equation for $x$: $75^2-x^2=225$ $x^2=75^2-225$ $x^2=5625-225$ $x^2=5400$ $x=\pm\sqrt{5400}$ $x=\pm 30\sqrt 6$ As $x\geq 0$, the only solution is: $x=30\sqrt 6$ feet
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