Answer
$x^2+10x+16=0$
Work Step by Step
Write the quadratic as the product of two linear factors and the leading coefficient: $a(x-r_1)(x-r_2)=0$, where $r_1$ and $r_2$ are the solutions.
$a[x-(-2)][x-(-8)]=0~~$ (Make $a=1$ since it can be any real number except $0$)
$(x+2)(x+8)=0$
$x^2+8x+2x+16=0$
$x^2+10x+16=0$ (general form)
