Algebra 2 (1st Edition)

Published by McDougal Littell
ISBN 10: 0618595414
ISBN 13: 978-0-61859-541-9

Chapter 9 Quadratic Relations and Conic Sections - Mixed Review of Problem Solving - Lessons 9.1-9.4 - Page 641: 5c

Answer

See below

Work Step by Step

Find the radius: $$v=\sqrt 9.8 \mu r\\v^2=9.8 \mu r\\r=\frac{v^2}{\mu 9.8}$$
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