Answer
See below
Work Step by Step
When it opens to the right, the point on the parabola will be $(8,\frac{22.4}{2})$
The equation has the form $y^2=4px$
Find $p=\frac{y^2}{4x}=\frac{11.2^2}{32}=3.92$
Hence $y^2=4px=4(3.92)x=15.68x$
Algebra 2 (1st Edition)
by Larson, Ron; Boswell, Laurie; Kanold, Timothy D.; Stiff, Lee
Published by
McDougal Littell
ISBN 10:
0618595414
ISBN 13:
978-0-61859-541-9
Chapter 9 Quadratic Relations and Conic Sections - Mixed Review of Problem Solving - Lessons 9.1-9.4 - Page 641: 1b
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