Algebra 2 (1st Edition)

Published by McDougal Littell
ISBN 10: 0618595414
ISBN 13: 978-0-61859-541-9

Chapter 9 Quadratic Relations and Conic Sections - Mixed Review of Problem Solving - Lessons 9.1-9.4 - Page 641: 1a

Answer

See below

Work Step by Step

We can see that the point $(\frac{22.4}{2},8)$ is on the parabola and the parabola is opening upwards. The equation has the form $x^2=4py$ Find $p=\frac{x^2}{4y}=\frac{11.2^2}{32}=3.92$
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