Answer
See below
Work Step by Step
If the vertex of an ellipse is at $(\pm a,0)$ and the vertex is at $(0,\pm b)$, then the equation of the ellipse is $\frac{x^2}{a^2(1-e^2)}+\frac{y^2}{b^2}=1$
Hence here $a=8,ae=5$, and the equation is: $\frac{x^2}{64-25}+\frac{y^2}{64}=1\\\frac{x^2}{39}+\frac{y^2}{64}=1$