Answer
See below
Work Step by Step
Given $$81x^2+9y^2=729\\\frac{x^2}{9}+\frac{y^2}{81}=1$$
The denominator of $x^2$ is smaller than $y^2$, so the transverse axis is vertical.
Identify the vertices, foci, and asymptotes. Note that $a=3$ and
$b=9$. The $x^2-term$ is negative, so the transverse axis is vertical, and the vertices are at $(0,\pm 3)$.
Draw the ellipse.
