Answer
See below
Work Step by Step
Rewrite $16x^2+25y^2=400$ in standard form as $\frac{x^2}{25}+\frac{y^2}{16}=1$
Note that $a=5$ and $b=4$. We can find out that $c\approx6.4$ The major axis is horizontal. The vertices are at $(\pm 5,0)$. The co-vertices are at $(0,\pm 4)$. The foci are at $(0, \pm 6.4)$.
Draw the ellipse.
