Answer
See below
Work Step by Step
Given $x^2+6x-y+16=0$
We can see that $a=1\\b=0\\c=0$
We will find the discriminant of the given equation $=b^2-4ac\\=0^2-4(1)(0)\\=0$
Since the discriminant $= 0$, the conic is a parabola.
To graph the parabola, first complete the square in x.
$x^2+6x-y+16=0\\x^2+6x+9+7=y\\y-7=(x+3)^2$
From the equation, you can see that the center is at $(-3,7)$
