Answer
See below
Work Step by Step
Given: $16x^2+9y^2+32x-18y=119\\x^2+y^2+2x+6y=15$
Multiply the second equation by $-16$ and add it to the first equation:
$-7y^2-114y+121=0$
We found $y_1=1\\y_2=-\frac{121}{7}$
The second solution does not make sense; thus we will take only the first solution.
Find the values of $x$
$x^2+1^2+2x+6(1)=15\\x^2+2x-8=0\\\rightarrow x_1=-4\lor x_2=2$