Chapter 9 Quadratic Relations and Conic Sections - 9.7 Solve Quadratic Systems - 9.7 Exercises - Quiz for Lessons 9.6-9.7 - Page 664: 2

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The vertex is at $(-5, 2)$ and the focus is at $(-5, -1)$ The standard form for the parabola: $(x-h)^2=-4p(y-k)$ The distance from $(-5,2)$ to $(-5,-1)$ is $3$, so $p=3$ Plug in the given values: $(x+5)^2=-12(y-2)$