Algebra 2 (1st Edition)

Published by McDougal Littell
ISBN 10: 0618595414
ISBN 13: 978-0-61859-541-9

Chapter 9 Quadratic Relations and Conic Sections - 9.2 Graph and Write Equations of Parabolas - 9.2 Exercises - Skill Practice - Page 623: 2

Answer

Check the vertex, focus, directrix, axis of symmetry, opening direction.

Work Step by Step

We are given the equations: $$\begin{align*} x^2&=4py\tag1\\ y^2&=4px.\tag2 \end{align*}$$ Both equations are graphically represented by a parabola with vertex $(0,0)$. The focus of parabola $(1)$ is on the $y$-axis at $(0,p)$, while the focus of parabola $(2)$ is on the $x$-axis at $(p,0)$. The directrix of parabola $(1)$ is a horizontal line ($y=-p$), while the directrix of parabola $(2)$ is a vertical line ($x=-p$). The axis of symmetry of parabola $(1)$ is vertical ($x=0$), while the axis of symmetry of parabola $(2)$ is horizontal ($y=0$). The graph of parabola $(1)$ opens up (for $p>0$) or down (for $p<0$), while the graph of parabola $(2)$ opens left (for $p<0$) or right (for $p>0$).
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.