Answer
See below
Work Step by Step
The equation in standard form: $4y^2=x\\y^2=\frac{1}{4}x$
Identify the focus, directrix, and axis of symmetry. The equation has the form $y^2=4px$ where $p=\frac{1}{16}$. The focus is $(\frac{1}{16},0)$. The directrix is $x =-p=-\frac{1}{16}$. Because $y$ is squared, the axis of symmetry is the x-axis.
Find some values and plot points:
$x=1 \rightarrow y=\pm 0.5\\x=2 \rightarrow y=\pm 0.71\\x=3 \rightarrow y=\pm 0.87\\x=4 \rightarrow y=\pm 1\\x=5 \rightarrow y=\pm 1.12$