Answer
$$\frac{5x^2-11x-9}{\left(x+8\right)\left(x-3\right)}$$
Work Step by Step
Creating like denominators and then simplifying, we find:
$$\frac{5x\left(x-3\right)}{\left(x+8\right)\left(x-3\right)}+\frac{4x-9}{\left(x+8\right)\left(x-3\right)}\\ \frac{5x\left(x-3\right)+4x-9}{\left(x+8\right)\left(x-3\right)}\\ \frac{5x^2-11x-9}{\left(x+8\right)\left(x-3\right)}$$
