Answer
$$=\frac{x^2+9x+12}{2x\left(x+3\right)}$$
Work Step by Step
Creating like denominators and then simplifying, we find:
$$\frac{2x}{2x\left(x+3\right)}+\frac{\left(x+4\right)\left(x+3\right)}{2x\left(x+3\right)}\\ =\frac{2x+\left(x+4\right)\left(x+3\right)}{2x\left(x+3\right)}\\ =\frac{x^2+9x+12}{2x\left(x+3\right)}$$
