Algebra 2 (1st Edition)

Published by McDougal Littell
ISBN 10: 0618595414
ISBN 13: 978-0-61859-541-9

Chapter 8 Rational Functions - Chapter Review - Page 605: 21

Answer

$\frac{(4x-1)3x}{(x-3)(x-4)}$

Work Step by Step

$\frac{16x^2-8x+1}{x^3-7x^2+12x}\div\frac{20x^2-5x}{15x^3}=\frac{16x^2-8x+1}{x^3-7x^2+12x}\frac{15x^3}{20x^2-5x}=\frac{(4x-1)^2}{x(x-3)(x-4)}\frac{15x^3}{5x(4x-1)}=\frac{(4x-1)^215x^3}{x(x-3)(x-4)5x(4x-1)}=\frac{(4x-1)3x}{(x-3)(x-4)}$
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