Answer
$$\frac{x^2-8x-4}{\left(x+4\right)\left(x-4\right)}$$
Work Step by Step
Simplifying the expression by creating like denominators, we find:
$$\frac{2x}{x+4}-\frac{x^2+4}{\left(x+4\right)\left(x-4\right)} \\ \frac{2x\left(x-4\right)}{\left(x+4\right)\left(x-4\right)}-\frac{x^2+4}{\left(x+4\right)\left(x-4\right)} \\ \frac{2x\left(x-4\right)-\left(x^2+4\right)}{\left(x+4\right)\left(x-4\right)} \\ \frac{x^2-8x-4}{\left(x+4\right)\left(x-4\right)}$$
