Answer
$$\frac{2x^2+3x+9}{\left(x-3\right)\left(x+1\right)}$$
Work Step by Step
Simplifying the expression by creating like denominators, we find:
$$\frac{9\left(x+1\right)}{\left(x-3\right)\left(x+1\right)}+\frac{2x\left(x-3\right)}{\left(x+1\right)\left(x-3\right)} \\ \frac{9\left(x+1\right)+2x\left(x-3\right)}{\left(x-3\right)\left(x+1\right)} \\ \frac{2x^2+3x+9}{\left(x-3\right)\left(x+1\right)}$$
