Answer
0.028 cm
Work Step by Step
From part a, we found: $x=-\frac{\ln\frac{I}{I_0}}{\mu}$
Substitute $I=0.3I_0\\\mu=43$
We have: $x=-\frac{\ln\frac{0.3I_0}{I_0}}{43}=-\frac{\ln 0.3}{3.2}\approx 0.028$ cm
Algebra 2 (1st Edition)
by Larson, Ron; Boswell, Laurie; Kanold, Timothy D.; Stiff, Lee
Published by
McDougal Littell
ISBN 10:
0618595414
ISBN 13:
978-0-61859-541-9
Chapter 7 Exponential and Logarithmic Functions - 7.6 Solve Exponential and Logarithmic Equations - 7.6 Exercises - Problem Solving - Page 522: 60c
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