Answer
$=\frac{\sqrt x}{4x^6}$
Work Step by Step
$\frac{2\sqrt x .\sqrt x^3}{\sqrt 64x^{15}}$
$=\frac{2x^{\frac{1}{2}}. x^{\frac{3}{2}}}{8x^7.x^{\frac{1}{2}}}$
$=\frac{2x^{\frac{4}{2}}}{8x^{\frac{15}{2}}}$
$=\frac{2}{8x^{\frac{11}{2}}}$
$=\frac{1}{4x^{\frac{11}{2}}}$
$=\frac{1}{4\sqrt x^{11}}$
$=\frac{\sqrt x}{4x^6}$