Answer
$=y^{\frac{1}{2}}(x^{\frac{3}{4}}+2x^{\frac{2}{3}})$
Work Step by Step
$(x^6y^4)^{\frac{1}{8}}+2(x^{\frac{1}{3}}y^{\frac{1}{4}})^2$
$=(x^{\frac{3}{4}}y^{\frac{1}{2}})+2(x^{\frac{2}{3}}y^{\frac{1}{2}})$
$=(x^{\frac{3}{4}}y^{\frac{1}{2}})+2x^{\frac{2}{3}}y^{\frac{1}{2}}$
$=y^{\frac{1}{2}}(x^{\frac{3}{4}}y^{\frac{1}{2}}y^{\frac{-1}{2}}+2x^{\frac{2}{3}}y^{\frac{1}{2}}y^{\frac{-1}{2}})$
$=y^{\frac{1}{2}}(x^{\frac{3}{4}}y^0+2x^{\frac{2}{3}}y^0)$
$=y^{\frac{1}{2}}(x^{\frac{3}{4}}+2x^{\frac{2}{3}})$