Answer
$x=5$, $x=-4$ or $x=\pm\frac{3}{\sqrt2}$
Work Step by Step
$f(x)=2x^4-2x^3-49x^2+9x+180=(x-5)(x+4)(2x^2-9)=0$
Thus $x=5$, $x=-4$ or $x=\pm\frac{3}{\sqrt2}$
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