Answer
See below
Work Step by Step
Given: $f(x)=(x-3)(x+2)^2(x+3)^2=(x-3)(x+2)(x+2)(x+3)(x+3)$
Find x-intercepts: $x-3=0 \rightarrow x=3\\x+2=0\rightarrow x=-2\\x+3=0\rightarrow x=-3$
Let's find some points:
$x=-5 \rightarrow y=-288\\x=-1\rightarrow y=-16\\ x=1\rightarrow y=-288 \\x=4 \rightarrow y=1764$
$f(x) \rightarrow -\infty$ as $x \rightarrow -\infty$
$f(x) \rightarrow \infty $ as $x \rightarrow \infty$