Answer
Positive real zeros = 2 or 0
Negative real zeros= 1
Minimum number of complex roots = Zero
Work Step by Step
Here, we have $f(x)=x^3+x^2-x-1$
By Descartes' Rule, we have either $2$ or $0$ positive real roots.
Now, $f(-x)=-x^3+x^2+x-1$
By Descartes' Rule, we have $1$ negative real root.
Positive real zeros = 2 or 0
Negative real zeros= 1
Minimum number of complex roots = Zero