Answer
Positive real root =1
Negative real root= 1
Imaginary roots: 2
Work Step by Step
In the given polynomial of degree $4$ , there are $4$ zeros.
By Descartes' Rule, we have $1$ positive real root.
$f(-x)=(-x)^4-(-x)^2-6=x^4-x^2-6$
The above polynomial shows that there is 1 sign change.
By Descartes' Rule, we have $1$ negative real root.
Thus, the other two roots must be imaginary.
Positive real root =1
Negative real root= 1
Imaginary roots: 2