Answer
Positive real root = 2 or 0
Negative real root= 1
Imaginary roots: 2 or 0
Work Step by Step
In the given polynomial of degree $3$, there are $3$ zeros.
Here, we have $g(x)=x^3-4x^2+8x+7$
By Descartes' Rule, we have either $2$ or $0$ positive real roots.
Now, $g(x)=-x^3-4x^2-8x+7$
The above polynomial shows that there is one sign change.
By Descartes' Rule, we have $1$ negative real root.
Thus, the other two roots must be imaginary.
Hence, positive real roots = 2 or 0
Negative real root = 1
Imaginary roots = 2 or 0