Answer
See below
Work Step by Step
Given: $f(x)=2x^4-5x^3+10x^2-9$
The leading coefficient is $\pm 1,\pm 2, \pm 4$
The constant term is $\pm 1,\pm3$
The possible rational zeros are: $\pm \frac{1}{1},\pm \frac{3}{1},\pm \frac{1}{2},\pm \frac{3}{2},\pm \frac{1}{4},\pm \frac{3}{4}$
Hence, there are $12$ possible rational zeros.