Answer
$a^{-m}=\dfrac{1}{a^m}$
Work Step by Step
As per the zero property, we have $a^0=1$
Thus, $\dfrac{1}{a^m}=\dfrac{a^0}{a^m}$ ...(1)
Now, we need to use the quotient property.
$\dfrac{a^0}{a^m}=a^{0-m}=a^{-m}$
Equation (1) becomes: $\dfrac{1}{a^m}=\dfrac{a^0}{a^m}=a^{-m}$
This gives: $a^{-m}=\dfrac{1}{a^m}$
Hence, the result has been verified.