Answer
$4x^{-1} y^3$
Work Step by Step
Here, we have $3 x^{3} y^{2}=\dfrac{12 x^{2} y^{5}}{a}$
Now,
$a= \dfrac{12 x^{2} y^{5}}{3 x^{3} y^{2}}$
This gives:
$a= 4 x^{2-3} \times y^{5-2}=4x^{-1} y^3$
Algebra 2 (1st Edition)
by Larson, Ron; Boswell, Laurie; Kanold, Timothy D.; Stiff, Lee
Published by
McDougal Littell
ISBN 10:
0618595414
ISBN 13:
978-0-61859-541-9
Chapter 5 Polynomials and Polynomial Functions - 5.1 Use Properties of Exponents - 5.1 Exercises - Skill Practice - Page 334: 44
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